I wasn't sure, so I asked:

> Higher voltage systems experience lower power losses over the same distance compared to lower voltage systems. This is due to the fact that power loss in a conductor is proportional to the square of the current. By using higher voltage, you can transmit the same amount of power with less current, reducing resistive losses in the wires.

Woosh. There's potentially a joke in there if you read it again while understanding the applicable equation for electrical power.

(V^2)/R

Woosh indeed, haha. I'm no EE but it sounded plausible. Maybe I'll get the joke if I do some actual reading. :)

12 Volts is 12 Watts per Amp.

48 Volts is 48 Watts per Amp.